Answer
$L=4.65\mu m$
Work Step by Step
We know that;
$(N_2-N_1)\lambda=L(n_2-n1)$
We plug in the known values to obtain:
$1.5(620=L(1.65-1.45))$
$L=4650nm=4.65\times 10^3\times 10^{-9}=4.65\times 10^{-6}=4.65\mu m$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 35 - Interference - Problems - Page 1074: 9b
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