Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 35 - Interference - Problems - Page 1074: 3a

Answer

$L = 3.60~\mu m$

Work Step by Step

We can find an expression for the wavelength in glass: $\frac{\lambda}{1.60}$ We can find an expression for the wavelength in plastic: $\frac{\lambda}{1.50}$ We can find $L$ such that the difference in the number of cycles is equal to $\frac{5.65}{2\pi}$: $\frac{L}{\lambda/1.60}-\frac{L}{\lambda/1.50} = \frac{5.65}{2\pi}$ $1.60~L-1.50~L = \frac{5.65}{2\pi}~\lambda$ $L = (\frac{1}{0.1})(\frac{5.65}{2\pi})~(400~nm)$ $L = 3.60~\mu m$
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