Answer
$+0.20$
Work Step by Step
Recall that the magnification of the system, $M$, is the product of the magnification of each lens.
$M=m_1m_2$
From equation 34-6, we know that $m=-i/p$; therefore we can obtain.
$M=(-i/p)(-i_f/p_f)$
$M=(-1.0m/1.0m)(-0.60m/3.0m)$
$M=+0.20$
