Answer
$1.0$
Work Step by Step
First we can use the given values and our answer to part A in equation 34-6 to find the magnification of each lens.
$m_1=-i_1/p_1$
$m_1=-(40cm)/40cm$
$m_1=-1.0$
$m_2=-i_2/p_2$
$m_2=-(-30cm)/(-30cm)$
$m_2=-1.0$
Recall that the magnification of the system, $M$, is the product of the magnification of each lens.
$M=m_1m_2$
$M=(-1.0)(-1.0)$
$M=+1.0$
