Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 2 - Motion Along a Straight Line - Problems - Page 36: 69

Answer

In 16 seconds, the runner runs a distance of $~~100~m$

Work Step by Step

To find the distance that the runner runs, we can find the area under the velocity versus time curve for the runner. We can divide this area into four parts, including a triangle ($0~s$ to $2~s$), a rectangle ($2~s$ to $10~s$), a triangle ($10~s$ to $12~s$), and a rectangle ($10~s$ to $16~s$) We can calculate each area separately: $A_1 = \frac{1}{2}(2.0~s)(8.0~m/s) = 8.0~m$ $A_2 = (8.0~s)(8.0~m/s) = 64~m$ $A_3 = \frac{1}{2}(2.0~s)(4.0~m/s) = 4.0~m$ $A_4 = (6.0~s)(4.0~m/s) = 24~m$ We can find the total area: $A = (8.0~m)+(64~m)+(4.0~m)+(24~m)$ $A = 100~m$ In 16 seconds, the runner runs a distance of $~~100~m$
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