Answer
$a_{(4)}=-42\frac{m}{s^2}$
Work Step by Step
As $v=\frac{dx}{dt}=6t-6t^2$,
$a=\frac{dv}{dt}=6-12t$
Next, we substitute $t=4$ in the expression to find the value of $a$ at $t=4s$:
$a_{(4)}=6-12(4)=6-48=-42\frac{m}{s^2}$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 2 - Motion Along a Straight Line - Problems - Page 33: 22m
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