Answer
$v_{(3)}=-36\frac{m}{s}$
Work Step by Step
We need to differentiate $x=3t^2-2t^3$ to find $v$:
Therefore, $v=\frac{dx}{dt}=6t-6t^2$
For $t=3s$
$v_{(3)}=6(3)-6(3)^2=-36\frac{m}{s}$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 2 - Motion Along a Straight Line - Problems - Page 33: 22h
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