Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 16 - Waves-I - Problems - Page 478: 91b

Answer

The tension in the rope is $~~240~N$

Work Step by Step

We can find the wave speed: $v = \lambda~f$ $v = 2L~f$ $v = (2)(2.0~m)~(5.0~Hz)$ $v = 20~m/s$ We can find the tension in the rope: $v = \sqrt{\frac{\tau}{\mu}}$ $v = \sqrt{\frac{\tau}{m/L}}$ $v = \sqrt{\frac{\tau~L}{m}}$ $v^2 = \frac{\tau~L}{m}$ $\tau = \frac{v^2~m}{L}$ $\tau = \frac{(20~m/s)^2~(1.2~kg)}{2.0~m}$ $\tau = 240~N$ The tension in the rope is $~~240~N$
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