Answer
396 Nm
Work Step by Step
The power of the energy (P) = 74.6Kw
The angular speed ($\omega$) = 1800 rev/min = 188.495 rad/s
Since $P = \tau.\omega$ :
$\tau=\frac{P}{\omega}$
$\tau=\frac{74.6\times10^{3}}{188.495}$
$\tau=395.76 Nm$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 10 - Rotation - Problems - Page 291: 59
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