Answer
Please see the work below.
Work Step by Step
We know that
$Nsin{\theta}=\frac{mv^2}{r}$............eq(1)
and $Ncos{\theta}$=mg...........eq(2)
Dividing eq(1) by eq(2), we obtain:
$tan{\theta}=\frac{v^2}{rg}$
This can be rearranged as:
$\frac{v^2}{r}=gtan{\theta}$
$\implies a=gtan{\theta}$
We plug in the known values to obtain:
$a=(10)(\frac{1}{2})$
$a=5\frac{m}{s^2}$
