Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 5 - Exercises and Problems - Page 89: 75

Answer

r = 7600 meters

Work Step by Step

We find the speed of the plane: $v=(340)(1.8)=612m/s$ We know that the centripetal acceleration cannot exceed 5g's, for we must subtract one from 6g's since gravity is acting downward. Thus: $5g =\frac{612^2}{r} \\ \fbox{ r = 7600 meters}$
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