Answer
Please see the work below.
Work Step by Step
We know that according to given scenario
$Tcos{\theta}=\frac{mv^2}{r}$...........eq(1)
and $Tsin{\theta}=mg$..............eq(2)
dividing eq(1) by eq(2), we obtain:
$cot{\theta}=\frac{v^2}{rg}$
This can be rearranged as:
$v^2=rgcot{\theta}$
$\implies v=\sqrt{rgcot{\theta}}$
We plug in the known values to obtain:
$v=8.2\frac{m}{s}$
Thus, it is not moving faster than the bullet.
