Answer
Please see the work below.
Work Step by Step
We know that
$A_x+B_x=0$
$|Acos (35)|+B_x=0$
$(1.0)cos(35)+B_x=0$
$B_x=-0.8192m$
We can find the direction of B as
$\theta=180-cos^{-1}(\frac{B_x}{B})$
$\theta=180-cos^{-1}(\frac{0.8192}{1.8})=117^{\circ}$
