Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 3 - Exercises and Problems - Page 48: 41

Answer

Please see the work below.

Work Step by Step

We know that $\omega=\frac{2\pi \frac{rad}{s}}{3600s}=0.001745\frac{rad}{s}$ $r=7.5cm=0.075m$ $v=r\omega$ We plug in the known values to obtain: $v=(0.075)(0.001745\frac{rad}{s})=1.3\times 10^{-4}\frac{m}{s}$ We also know that $a=\frac{v^2}{r}$ We plug in the known values to obtain: $a=\frac{1.3\times 10^{-4}}{0.075}$ $a=2.28\times 10^{-7}\frac{m}{s^2}$
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