Answer
a) $\sqrt5A$
b) $\sqrt{10}A$
Work Step by Step
We find the magnitudes using the equation for distance:
a) $d = \sqrt{(2A)^2 + A^2} =\sqrt5A$
b) $d = \sqrt{(3A)^2 + (-A)^2} =\sqrt{10}A$
Essential University Physics: Volume 1 (3rd Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0321993721
ISBN 13:
978-0-32199-372-4
Chapter 3 - Exercises and Problems - Page 48: 45
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