Answer
Please see the work below.
Work Step by Step
(a) We know that
$T_1V_1^{\gamma-1}=T_2V_2^{\gamma-1}$
This can be rearranged as:
$T_2=T_1(\frac{V_1}{V_2})^{\gamma-1}$
We plug in the known values to obtain:
$T_2=320K\times (10.2)^{1.4-1}$
$T_2=810K$
(b) We know that
$P_1V_1^{\gamma}=P_2V_2^{\gamma}$
This can be rearranged as:
$P_2=P_1(\frac{V_1}{V_2})^{\gamma}$
We plug in the known values to obtain:
$P_2=1atm(10.2)^{1.4}$
$P_2=25.8atm$
