Answer
.61 times the original volume.
Work Step by Step
We use the known equation to find:
$(\frac{V_2}{V_1})^{\gamma}=\frac{p_1}{p_2}$
$(\frac{V_2}{V_1})^{1.4}=.5$
$(\frac{V_2}{V_1})^{1.4}=.61$
Essential University Physics: Volume 1 (3rd Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0321993721
ISBN 13:
978-0-32199-372-4
Chapter 18 - Exercises and Problems - Page 331: 42
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