Answer
Please see the work below.
Work Step by Step
We know that
$\frac{dQ}{dt}=\frac{dU}{dt}-\frac{dW}{dt}$
We plug in the known values to obtain:
$\frac{dQ}{dt}=(500)-(120)$
$\frac{dQ}{dt}=380W$
Essential University Physics: Volume 1 (3rd Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0321993721
ISBN 13:
978-0-32199-372-4
Chapter 18 - Exercises and Problems - Page 331: 33
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