Answer
Please see the work below.
Work Step by Step
We know that
$\frac{P_2V_2}{T_2}=\frac{P_1V_1}{T_1}$
This can be rearranged as:
$V_2=\frac{T_2P_1V_1}{T_1P_2}$
We plug in the known values to obtain:
$V_2=\frac{(273-10)(1.0)(8.0)}{(273+20)(0.65)}$
$V_2=11L$