Answer
Please see the work below.
Work Step by Step
We know that
$v=\sqrt{\frac{3kT}{m}}$
We plug in the known values to obtain:
$v=\sqrt{\frac{(3)(1.38\times 10^{-23})(800)}{3.35\times 10^{-27}}}$
$v=3100\frac{m}{s}$
Essential University Physics: Volume 1 (3rd Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0321993721
ISBN 13:
978-0-32199-372-4
Chapter 17 - Exercises and Problems - Page 313: 23
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