Answer
Please see the work below.
Work Step by Step
We know that
$PV=NKT$
This can be rearranged as:
$\frac{N}{V}=\frac{P}{kT}$
We plug in the known values to obtain:
$\frac{N}{V}=\frac{0.03}{(1.38\times 10^{-23})(2\times 10^6)}$
$\frac{N}{V}=1.1\times 10^{15}\frac{moleucles }{m^3}$