Answer
$.4347$
Work Step by Step
We first find the angular velocity:
$\omega = \frac{2\pi}{1.8}=3.491$
We now find the coefficient of friction:
$\omega^2 A m_2 =\mu m_2g$
$\mu = \frac{\omega^2 A}{g}$
$\mu = \frac{3.491^2 (.35)}{9.81}=.4347$
Essential University Physics: Volume 1 (3rd Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0321993721
ISBN 13:
978-0-32199-372-4
Chapter 13 - Exercises and Problems - Page 240: 74
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