Answer
$\frac{5}{8}MR^2$
Work Step by Step
We add the inertias of the inner and outer rings using the equation for the moment of inertia of a ring:
$ I =(\frac{1}{2}M)(\frac{1}{2}R)^2+(\frac{M}{2})R^2=\frac{5}{8}MR^2$
Essential University Physics: Volume 1 (3rd Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0321993721
ISBN 13:
978-0-32199-372-4
Chapter 10 - Exercises and Problems - Page 185: 50
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