Answer
(a) $3.2\times 10^{38}Kgm^2$
(b) $1.8\times 10^{34}Nm$
Work Step by Step
(a) We know that
Rotational inertial of solid sphere$=\frac{2}{5}MR^2$
We plug in the known values to obtain:
Rotational inertial of solid sphere$=\frac{2}{5}(2.3\times 1.99\times 10^3)(13155)^2=3.2\times 10^{38}Kgm^2$
(b) We can find the torque as follows
$\tau=I\alpha $
We plug in the known values to obtain:
$\tau=3.2\times 10^{38}\times 5.6\times 10^{-5}=1.8\times 10^{34}Nm$
