Chapter 7 - Circular Motion and Gravitation - Learning Path Questions and Exercises - Exercises - Page 263: 50

$5.48rad/s^{2}$

Centripetal acceleration $=10g$ $m\frac{v^{2}}{r}=10g$ $v^{2}=\frac{10\times9.8\times0.35}{1.5}=22.9$ $v=4.79m/s$ $r\omega=4.79$ Angular speed =$\omega=\frac{4.79}{0.35}=13.7rad/s$ Thus, the constant acceleration $=\frac{13.7-0}{2.5}=5.48rad/s^{2}$