Chapter 7 - Circular Motion and Gravitation - Learning Path Questions and Exercises - Exercises - Page 263: 48

We know, that $\omega^{2}=\omega_{0}^{2}-2a\Delta\theta$, let a be the angular acceleration. i.e. $\Delta\theta=\frac{\omega^{2}-\omega_{0}^{2}}{2a}$ i.e. $\theta-\theta_{0}=\frac{\omega^{2}-\omega_{0}^{2}}{2a}$ i.e. $\theta=\theta_{0}+\frac{\omega^{2}-\omega_{0}^{2}}{2a}$

We know, that $\omega^{2}=\omega_{0}^{2}-2a\Delta\theta$, let a be the angular acceleration. i.e. $\Delta\theta=\frac{\omega^{2}-\omega_{0}^{2}}{2a}$ i.e. $\theta-\theta_{0}=\frac{\omega^{2}-\omega_{0}^{2}}{2a}$ i.e. $\theta=\theta_{0}+\frac{\omega^{2}-\omega_{0}^{2}}{2a}$