Answer
a). $8rad/s^{2}$
b). $16$
Work Step by Step
a). Angular acceleration =$\frac{\Delta\omega}{\Delta t}=\frac{40}{5}=8 rad/s^{2}$
b). $\omega^{2}=\omega_{0}^{2}+2a\Delta\theta$
Thus, $\Delta\theta=\frac{40^{2}}{2\times8}=100rad$
No of revolutions $=\frac{100}{2pi}=16$