Answer
$2.67m/s$
Work Step by Step
$d=2pi \times r=13.8m$
$v=\frac{d}{t}=\frac{13.8}{4.5}=3.07m/s$
Thus, $a_{c}=\frac{v^{2}}{r}=\frac{3.07^{2}}{2.2}=4.28m/s^{2}$
But the maximum acceleration the skate can provide is $3.25m/s^{2}$, so things will not work as he has planned.
For the figure to remain same, he must reduce his speed to,
$v=\sqrt (ar)=\sqrt (3.25\times2.2)=2.67m/s$
