Answer
a). (2) $(90^{\circ}-alpha)$
b). $57^{\circ}$
Work Step by Step
a). alpha = angle between surface of the mirror and incident ray.
So, incident angle with respect to the normal to the mirror surface is $(90^{\circ}-alpha)$.
Now, since angle of incidence = angle of reflection,
the angle between reflected ray and the normal will be $(90^{\circ}-alpha)$
b). alpha =$33^{\circ}$
Hence, the angle between the reflected ray and the normal is $90^{\circ}-33^{\circ}=57^{\circ}$
