Answer
$56.65^{\circ}$
Work Step by Step
By Snell's law,
$n_{air}\times sin(i)=n_{poly}\times sin(r)$
or, $1\times sin55^{\circ}=1.49\times sin(r)$
i.e. $r=33.35^{\circ}$
Thus, angle made by the refracted ray with the surface = $90^{\circ}-33.35^{\circ}=56.65^{\circ}$
