Chapter 18 - Basic Electric Circuits - Learning Path Questions and Exercises - Exercises - Page 653: 9

a) $1A$ b) $V_{8}=8 Volts$ $V_{4}=4 Volts$

a) equivalent resistance of $R_{1}$ and $R_{2} = \frac{R_{1}R_{2}}{R_{1}+R_{2}}=\frac{8\times8}{8+8}=4 Ohm$ Therefore, $R_{eq1}=4 Ohm$ Similarly, $R_{eq2}=4/2=2Ohm$ Thus, $R_{eq}=R_{eq1}+R_{eq2}=4+2=6 Ohm$ So, $I=12/6=2 A$ Current through each resistor = $2/2=1A$ b) $V_{8}=1\times8=8 Volts$ $V_{4}=1\times4=4 Volts$