College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 18 - Basic Electric Circuits - Learning Path Questions and Exercises - Exercises - Page 653: 11

Answer

$2.7$Ohm

Work Step by Step

Since $R_{2}$ and $R_{3}$ are in series they can be added up which is equal to $4+6=10Ohm$. Thus 10Ohm, 10Ohm and 6Ohm are in parallel. Hence, equivalent resistance = $\frac{1}{Re}=\frac{1}{10}+\frac{1}{10}+\frac{1}{6}=\frac{22}{60}$ equivalent resistance = $2.7Ohm$
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