Chapter 18 - Basic Electric Circuits - Learning Path Questions and Exercises - Exercises - Page 653: 14

a). $I_{1}=I_{2}=3A$ and $I_{3}=I_{4}=6A$ b). $V_{1}=V_{2}=6V$ and $V_{3}=V_{4}=12V$

a) $R_{eq}=0.8Ohm$ $i=V/R_{eq}=12/0.8=15A$ Potential across $R_{1}+R_{2}$ and $R_{4}$ are equal. So, $R_{4}\times i_{1}=(R_{1}+R_{2})\times(i-2i_{1})$ $i_{1}=6A$ Thus, $I_{1}=I_{2}=3A$ and $I_{3}=I_{4}=6A$ b) $V_{1}=3(2)=6V$ $V_{2}=3(2)=6V$ $V_{3}=6(2)=12V$ $V_{4}=6(2)=12V$