Answer
a). $10^{-12}s$
b). $4000cm/s$
Work Step by Step
a). $T=\frac{1}{f}=\frac{1}{10^{12}}s=10^{-12}s$
b). $v_{max}=\frac{4A}{T}=\frac{4\times 10^{-9}}{10^{-12}} =4000cm/s$
College Physics (7th Edition)
by Wilson, Jerry D.; Buffa, Anthony J.; Lou, Bo
Published by
Pearson
ISBN 10:
0-32160-183-1
ISBN 13:
978-0-32160-183-4
Chapter 13 - Vibrations and Waves - Learning Path Questions and Exercises - Exercises - Page 484: 8
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