Chapter 13 - Vibrations and Waves - Learning Path Questions and Exercises - Exercises - Page 484: 6

$v_{max}=0.224m/s$

$v_{max}=\sqrt (\frac{k}{m})A$ where k is the spring constant, m is the mass of the object and A is the amplitude of oscillation. k=10N/m m=0.50kg A=0.050m So, $v_{max}=\sqrt (\frac{10}{0.50})\times0.050=0.224m/s$