Answer
a). The answer is (1) x=0, as at x=0 there is no elastic potential energy, so all the energy of the system is kinetic, thus maximum speed is achieved here.
b). $v_{max}=A\sqrt \frac{k}{m}=0.10\times \sqrt \frac{100}{0.25}=2m/s$
Work Step by Step
a). The answer is (1) x=0, as at x=0 there is no elastic potential energy, so all the energy of the system is kinetic, thus maximum speed is achieved here.
b). $v_{max}=A\sqrt \frac{k}{m}=0.10\times \sqrt \frac{100}{0.25}=2m/s$