College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 6 - Problems - Page 233: 93

Answer

The maximum height is 6.1 meters

Work Step by Step

Let $h_2$ be the maximum height. We can use conservation of energy to find the maximum height: $mgh_2 = mgh_1 + \frac{1}{2}mv^2$ $h_2 = h_1 + \frac{v^2}{2g}$ $h_2 = 1.0~m + \frac{(10~m/s)^2}{(2)(9.80~m/s^2)}$ $h_2 = 6.1~m$ The maximum height is 6.1 meters.
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