College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 6 - Problems - Page 233: 92

Answer

The high jumper needs to be able to sprint at a speed of $4.85~m/s$

Work Step by Step

We can assume that all the kinetic energy will be converted into gravitational potential energy: $\frac{1}{2}mv^2 = mgh$ $v^2 = 2gh$ $v = \sqrt{2gh}$ $v = \sqrt{(2)(9.80~m/s^2)(1.2~m)}$ $v = 4.85~m/s$ The high jumper needs to be able to sprint at a speed of $4.85~m/s$
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