College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 6 - Problems - Page 233: 101

Answer

(a) $BMR = 2160~kcal/day$ (b) Jermaine would lose 232 grams of fat.

Work Step by Step

(a) We can find Jermaine's net intake of oxygen each day: $(0.015~mol/min)(24)(60~min) = 21.6 ~mol$ We can find his BMR: $BMR = \frac{21.6~mol/day}{0.010~mol/kcal} = 2160~kcal/day$ (b) We can find the amount of fat that is consumed: $\frac{2160~kcal/day}{9.3~kcal/gram} = 232~grams$ Jermaine would lose 232 grams of fat.
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