College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 22 - Problems - Page 866: 73

Answer

The intensity of the transmitted light is: $~I_0~cos^2 \theta_1~cos^2(\theta_1-\theta_2)$

Work Step by Step

We can use Malus' law to determine the intensity of the light after passing through the first polarizing sheet: $I_1 = I_0~cos^2~\theta_1$ The angle between the two polarizing sheets is $\theta_1-\theta_2$. We can find the intensity of the light after passing through the second polarizing sheet: $I_2 = I_1~cos^2(\theta_1-\theta_2)$ $I_2 = I_0~cos^2 \theta_1~cos^2(\theta_1-\theta_2)$ The intensity of the transmitted light is: $~I_0~cos^2 \theta_1~cos^2(\theta_1-\theta_2)$
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