College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 22 - Problems - Page 866: 72

Answer

103 stations can operate in the broadcast band.

Work Step by Step

We can find the frequency when the wavelength is $190~m$: $f = \frac{c}{\lambda} = \frac{3.0\times 10^8~m/s}{190~m} = 1.58\times 10^6~Hz = 1580~kHz$ We can find the frequency when the wavelength is $550~m$: $f = \frac{c}{\lambda} = \frac{3.0\times 10^8~m/s}{550~m} = 5.45\times 10^5~Hz = 545~kHz$ We can find the range: $1580~kHz - 545~kHz = 1035~kHz$ We can find the number of frequency bands 10 kHz wide that can fit inside this range: $\frac{1035~kHz}{10~kHz} = 103.5$ 103 stations can operate in the broadcast band.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.