Answer
The specific heat of lead is $126~J/kg~C^{\circ}$
Work Step by Step
We can find the specific heat of lead:
$Q = m~c~\Delta T$
$c = \frac{Q}{m~\Delta T}$
$c = \frac{880~J}{(0.350~kg)(20.0~C^{\circ})}$
$c = 126~J/kg~C^{\circ}$
The specific heat of lead is $126~J/kg~C^{\circ}$
