Answer
$v = 100~m/s$
Work Step by Step
We can find the man's speed:
$K = Q$
$\frac{1}{2}mv^2 = Q$
$v^2 = \frac{2Q}{m}$
$v = \sqrt{\frac{2Q}{m}}$
$v = \sqrt{\frac{(2)(418\times 10^3~J)}{83~kg}}$
$v = 100~m/s$
College Physics (4th Edition)
by Giambattista, Alan; Richardson, Betty; Richardson, Robert
Published by
McGraw-Hill Education
ISBN 10:
0073512141
ISBN 13:
978-0-07351-214-3
Chapter 14 - Problems - Page 534: 15
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