Answer
If 3.3% of the energy from the food could be converted into gravitational potential energy in a single jump, the athlete could jump to a height of $705~m$
Work Step by Step
We can convert the energy to units of joules:
$3000~kcal\times \frac{4186~J}{1~kcal} = 1.2558\times 10^7~J$
We can find the amount of energy that can be converted into gravitational potential energy:
$(0.033)(1.2558\times 10^7~J) = 4.14414\times 10^5~J$
We can find the height the athlete could jump:
$U_g = 4.14414\times 10^5~J$
$mgh = 4.14414\times 10^5~J$
$h = \frac{4.14414\times 10^5~J}{mg}$
$h = \frac{4.14414\times 10^5~J}{(60.0~kg)(9.80~m/s^2)}$
$h = 705~m$
If 3.3% of the energy from the food could be converted into gravitational potential energy in a single jump, the athlete could jump to a height of $705~m$
