Answer
The pressure at the higher temperature is $135~kPa$
Work Step by Step
We can find an expression for the original pressure:
$P_1V = nRT_1$
$P_1 = \frac{nRT_1}{V}$
We can find an expression for the new pressure:
$P_2V = nRT_2$
$P_2 = \frac{nRT_2}{V}$
We can divide $P_2$ by $P_1$ to find the new pressure $P_2$:
$\frac{P_2}{P_1} = \frac{\frac{nRT_2}{V}}{\frac{nRT_1}{V}}$
$P_2 = \frac{T_2}{T_1}~P_1$
$P_2 = \left(\frac{343~K}{293~K}\right)~(115~kPa)$
$P_2 = 135~kPa$
The pressure at the higher temperature is $135~kPa$
