Answer
The new temperature of the air is $400^{\circ}C$
Work Step by Step
We can find an expression for the original temperature:
$P_i~V_i = nRT_i$
$T_i = \frac{P_i~V_i}{nR}$
We can find the new temperature $T_f$:
$P_f~V_f = nRT_f$
$T_f = \frac{P_f~V_f}{nR}$
$T_f = \frac{(20.0~P_i)(0.111~V_i)}{nR}$
$T_f = (20.0)(0.111)\times \frac{P_i~V_i}{nR}$
$T_f = (20.0)(0.111)\times T_i$
$T_f = (20.0)(0.111)\times 303~K$
$T_f = 673~K$
$T_f = 400^{\circ}C$
The new temperature of the air is $400^{\circ}C$.
