Answer
27.21 seconds
Work Step by Step
We find the value of t:
$\Delta y = v_0t + \frac{1}{2}at^2 $
$5300 = 132.2t + \frac{1}{2}(4.6)t^2 $
$0 = -5300+ 132.2t + 2.3t^2 $
$\fbox{t=27.21 seconds}$
Essential University Physics: Volume 1 (4th Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0-134-98855-8
ISBN 13:
978-0-13498-855-9
Chapter 2 - Exercises and Problems - Page 32: 80
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