Answer
Please see the work below.
Work Step by Step
We know that
$v^2=2gI_{\circ}d$
$v=\sqrt{2gI_{\circ}d}$
We plug in the known values to obtain:
$v=\sqrt{(2)(1.8)(100)}$
$v=19\frac{m}{s}$
Essential University Physics: Volume 1 (4th Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0-134-98855-8
ISBN 13:
978-0-13498-855-9
Chapter 2 - Exercises and Problems - Page 32: 74
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