Answer
Please see the work below.
Work Step by Step
We know that
$Q=mc\Delta T$
This can be rearranged as:
$c=\frac{Q}{m\Delta T}$
We plug in the known values to obtain:
$c=\frac{7500}{(1)(3.0)}$
$c=2500\frac{J}{Kg \space C}$
Essential University Physics: Volume 1 (4th Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0-134-98855-8
ISBN 13:
978-0-13498-855-9
Chapter 16 - Section 16.4 - Exercises and Problems - Page 309: 20
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