Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 16 - Section 16.4 - Exercises and Problems - Page 309: 12

Answer

Please see the work below.

Work Step by Step

We know that $T_F=(\frac{9}{5})T_C+32$ We plug in the known values to obtain: $T_F=(\frac{9}{5})(-15)+32$ $T_F=5.0F^{\circ}$
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